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Hackerank Day 3: Intro to Conditional Statements solution in java


Day 3: Intro to Conditional Statements

Hackerank Day 3: Intro to Conditional Statements solution in java



    Algorithm

    input_number=N
    Step:-1   First check the input number is even or odd.
    Step:-2   if(even(N) AND(N==2 OR 4)) then print("Not Weird");
    Step:-3   else if(even(N) AND(N>=6 OR N<=20)) then  print("Weird");
    Step:-3   else if(even(N) AND (N>20)) then print("Not Weird");
    Step:-3   else print("Weird");

    Explanation

    At first, Check the number is even or odd by using modulo operator(%) and other techniques.If the input_number(N) is odd then directly print out "Weird" and if the input_number is even then there are three condition which are check one by one with the conditional statement.
    First condition:- if it is  2 or 4 then print out "Not Weird".
    Second Condition:- if it is within the range inclusion 6 to 20 (6<=N<=20) then print out "Weird".
    Third Condition:- if it greater than 20 (N>20) then print out "Not Weird".

    Examples

    Program

     import java.io.*;
    import java.math.*;
    import java.security.*;
    import java.text.*;
    import java.util.*;
    import java.util.concurrent.*;
    import java.util.regex.*;

    public class Solution {
    private static final Scanner scanner = new Scanner(System.in);
    public static void main(String[] args) {
    int N = scanner.nextInt();
    scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

    if(N%2==0 && (N==2 || N==4))
    {
    System.out.println("Not Weird");
    }

    else if(N%2==0 && (N>=6 && N<=20))
    {
    System.out.println("Weird");
    }
    else if(N%2==0 && N>20)
    {
    System.out.println("Not Weird");
    }
    else
    {
    System.out.println("Weird");
    }


    scanner.close();
    }
    }






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